🚀 Step-by-Step Guide to Find the Largest Number in an Array in Go
Finding the largest number in an array is a common task in programming. Let’s walk through a simple yet effective approach to accomplish this in Go.
📝 Steps to Follow
1️⃣ Loop through Each Value
Iterate through each element of the array or slice.
2️⃣ Declare the Initial Largest Value
Initialize a variable largest with the first element of the array:
largest := array[0]
3️⃣ Compare the Current Largest Value with Other Numbers
Compare the current largest value with each element in the array.
4️⃣ Update the Largest Value
Whenever you find a number greater than the current largest value, update largest to this new number.
5️⃣ Return the Largest Value
After completing the loop, return the largest number.
if len(nums) == 0 {
return 0 // handle empty slice case
}
largest := nums[0] // Step 2
for i := 1; i < len(nums); i++ { // Step 1
if nums[i] > largest { // Step 3
largest = nums[i] // Step 4
}
}
return largest // Step 5
}
Testing the function
tests := []struct {
name string
numbers []int
expected int
}{
{
name: “Mixed positive numbers”,
numbers: []int{45, 22, 68, 90, 12},
expected: 90,
},
{
name: “All negative numbers”,
numbers: []int{-5, -23, -1, -55},
expected: -1,
},
{
name: “All zeros”,
numbers: []int{0, 0, 0, 0, 0},
expected: 0,
},
}
for _, tt := range tests {
t.Run(tt.name, func(t *testing.T) {
got := findLargestNumber(tt.numbers)
if got != tt.expected {
t.Errorf(“findLargestNumber(%v) = %v, want %v”, tt.numbers, got, tt.expected)
}
})
}
}
Main Function
arr := []int{45, 22, 68, 90, 12}
fmt.Println(findLargestNumber(arr)) // Output: 90
}
Thanks for reading.
Kindly like and share other methods you know of in the comments below.
